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-3x^2-51x-216=0
a = -3; b = -51; c = -216;
Δ = b2-4ac
Δ = -512-4·(-3)·(-216)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-3}{2*-3}=\frac{48}{-6} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+3}{2*-3}=\frac{54}{-6} =-9 $
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